Optimal. Leaf size=99 \[ \frac{5 i a^3 \sec (c+d x)}{2 d}+\frac{5 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{5 i \sec (c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{6 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^2}{3 d} \]
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Rubi [A] time = 0.0660193, antiderivative size = 99, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {3498, 3486, 3770} \[ \frac{5 i a^3 \sec (c+d x)}{2 d}+\frac{5 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{5 i \sec (c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{6 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^2}{3 d} \]
Antiderivative was successfully verified.
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Rule 3498
Rule 3486
Rule 3770
Rubi steps
\begin{align*} \int \sec (c+d x) (a+i a \tan (c+d x))^3 \, dx &=\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^2}{3 d}+\frac{1}{3} (5 a) \int \sec (c+d x) (a+i a \tan (c+d x))^2 \, dx\\ &=\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^2}{3 d}+\frac{5 i \sec (c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{6 d}+\frac{1}{2} \left (5 a^2\right ) \int \sec (c+d x) (a+i a \tan (c+d x)) \, dx\\ &=\frac{5 i a^3 \sec (c+d x)}{2 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^2}{3 d}+\frac{5 i \sec (c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{6 d}+\frac{1}{2} \left (5 a^3\right ) \int \sec (c+d x) \, dx\\ &=\frac{5 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{5 i a^3 \sec (c+d x)}{2 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^2}{3 d}+\frac{5 i \sec (c+d x) \left (a^3+i a^3 \tan (c+d x)\right )}{6 d}\\ \end{align*}
Mathematica [A] time = 0.496575, size = 93, normalized size = 0.94 \[ \frac{a^3 (\cos (3 d x)+i \sin (3 d x)) \left (60 \tanh ^{-1}\left (\cos (c) \tan \left (\frac{d x}{2}\right )+\sin (c)\right )+i \sec ^3(c+d x) (9 i \sin (2 (c+d x))+24 \cos (2 (c+d x))+20)\right )}{12 d (\cos (d x)+i \sin (d x))^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.026, size = 167, normalized size = 1.7 \begin{align*}{\frac{-{\frac{i}{3}}{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{d \left ( \cos \left ( dx+c \right ) \right ) ^{3}}}+{\frac{{\frac{i}{3}}{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{d\cos \left ( dx+c \right ) }}+{\frac{{\frac{i}{3}}{a}^{3}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{d}}+{\frac{{\frac{2\,i}{3}}{a}^{3}\cos \left ( dx+c \right ) }{d}}-{\frac{3\,{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{3\,{a}^{3}\sin \left ( dx+c \right ) }{2\,d}}+{\frac{5\,{a}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{3\,i{a}^{3}}{d\cos \left ( dx+c \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.12551, size = 147, normalized size = 1.48 \begin{align*} \frac{9 \, a^{3}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} + \log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, a^{3} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + \frac{36 i \, a^{3}}{\cos \left (d x + c\right )} + \frac{4 i \,{\left (3 \, \cos \left (d x + c\right )^{2} - 1\right )} a^{3}}{\cos \left (d x + c\right )^{3}}}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.22749, size = 554, normalized size = 5.6 \begin{align*} \frac{66 i \, a^{3} e^{\left (5 i \, d x + 5 i \, c\right )} + 80 i \, a^{3} e^{\left (3 i \, d x + 3 i \, c\right )} + 30 i \, a^{3} e^{\left (i \, d x + i \, c\right )} + 15 \,{\left (a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{3}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} + i\right ) - 15 \,{\left (a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{3}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} - i\right )}{6 \,{\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} a^{3} \left (\int - 3 \tan ^{2}{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int 3 i \tan{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int - i \tan ^{3}{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int \sec{\left (c + d x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24123, size = 171, normalized size = 1.73 \begin{align*} \frac{15 \, a^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 15 \, a^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (9 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 18 i \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 48 i \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 9 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 22 i \, a^{3}\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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